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JEE Main & Advanced Physics Elasticity Question Bank Youngs Modulus and Breaking Stress

  • question_answer
    Two wires ?A? and ?B? of the same material have radii in the ratio 2 : 1 and lengths in the ratio 4 : 1. The ratio of the normal forces required to produce the same change in the lengths of these two wires is                                    [Haryana CEE 1996]

    A) 1 : 1       

    B)                 2 : 1

    C)                 1 : 4       

    D)                 1 : 2

    Correct Answer: A

    Solution :

        \[F=Y\times A\times \frac{l}{L}\]Þ\[F\propto \frac{{{r}^{2}}}{L}\] (Y and l are constant) \\[\frac{{{F}_{1}}}{{{F}_{2}}}={{\left( \frac{{{r}_{1}}}{{{r}_{2}}} \right)}^{2}}\left( \frac{{{L}_{2}}}{{{L}_{1}}} \right)={{\left( \frac{2}{1} \right)}^{2}}\left( \frac{1}{4} \right)=1\]Þ \[\frac{{{F}_{1}}}{{{F}_{2}}}=1:1\]


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