A) \[19.6\times {{10}^{10}}\,N/{{m}^{2}}\]
B) \[19.6\times {{10}^{15}}\,N/{{m}^{2}}\]
C) \[19.6\times {{10}^{18}}\,N/{{m}^{2}}\]
D) \[19.6\times {{10}^{20}}\,N/{{m}^{2}}\]
Correct Answer: A
Solution :
\[Y=\frac{MgL}{Al}=\frac{250\times 9.8\times 2}{50\times {{10}^{-6}}\times 0.5\times {{10}^{-3}}}\] \[=19.6\times {{10}^{10}}N/{{m}^{2}}\]
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