A) 0.5 mm
B) 0.25 mm
C) 0.05 mm
D) 5 mm
Correct Answer: C
Solution :
\[l=\frac{MgL}{YA}=\frac{1\times 10\times 1}{2\times {{10}^{11}}\times {{10}^{-6}}}=0.05\ mm\]
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