A) Nearly 17 N
B) Nearly 34 N
C) Nearly 51 N
D) Nearly 68 N
Correct Answer: C
Solution :
\[F=\frac{YAl}{L}\]\[=0.9\times {{10}^{11}}\times \pi \times {{(0.3\times {{10}^{-3}})}^{2}}\times \frac{0.2}{100}=51\ N\]
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