A) \[9.6\times {{10}^{-5}}\,m\]
B) \[9.6\times {{10}^{-11}}\,m\]
C) \[9.6\times {{10}^{-3}}\,m\]
D) 9.6 m
Correct Answer: B
Solution :
\[l=\frac{{{L}^{2}}dg}{2Y}=\frac{{{(8\times {{10}^{-2}})}^{2}}\times 1.5\times 9.8}{2\times 5\times {{10}^{8}}}\]\[=9.6\times {{10}^{-11}}m\]You need to login to perform this action.
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