A) \[1.0\times {{10}^{-7}}N\]
B) \[1.0\times {{10}^{7}}N\]
C) \[0.5\times {{10}^{-7}}N\]
D) \[0.5\times {{10}^{12}}\]dyne
Correct Answer: D
Solution :
If length of wire doubled then strain = 1 \[Y=\text{stress}\] Þ \[F=Y\times A\]\[={{10}^{12}}\times 0.5\]\[=0.5\times {{10}^{12}}dyne\]You need to login to perform this action.
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