A) 0.002
B) 0.001
C) 0.003
D) 0.01
Correct Answer: B
Solution :
Longitudinal strain \[\frac{l}{L}=\frac{\text{stress}}{Y}=\frac{{{10}^{6}}}{{{10}^{11}}}={{10}^{-5}}\] Percentage increase in length \[={{10}^{-5}}\times 100=0.001%\]You need to login to perform this action.
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