A) 3L
B) 4L
C) 2L
D) None of the above
Correct Answer: C
Solution :
\[Y={{10}^{4}}N/{{m}^{2}},A=2\times {{10}^{-4}}{{m}^{2}},F=2\times {{10}^{5}}dyne=2N\] \[l=\frac{FL}{AY}=\frac{2\times L}{2\times {{10}^{-4}}\times {{10}^{4}}}=L\] Final length = initial length + increment = 2LYou need to login to perform this action.
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