A) Different stresses and strains
B) The same stress and strain
C) The same strain but different stresses
D) The same stress but different strains
Correct Answer: D
Solution :
\[\text{Stress}=\frac{\text{Force}}{\text{area}}\]. In the present case, force applied and area of cross-section of wires are same, therefore stress has to be the same. \[\text{Strain}=\frac{\text{Stress}}{Y}\] Since the Young?s modulus of steel wire is greater than the copper wire, therefore, strain in case of steel wire is less than that in case of copper wire.You need to login to perform this action.
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