A) \[2:\sqrt{2}\]
B) \[\sqrt{2}:2\]
C) 1 : 1
D) 1 : 2
Correct Answer: C
Solution :
\[l=\frac{FL}{\pi {{r}^{2}}Y}\]\[\Rightarrow l\propto \frac{L}{{{r}^{2}}}\] (F and Y are constant) \[\frac{{{l}_{1}}}{{{l}_{2}}}=\frac{{{L}_{1}}}{{{L}_{2}}}{{\left( \frac{{{r}_{2}}}{{{r}_{1}}} \right)}^{2}}=\frac{1}{2}{{\left( \sqrt{2} \right)}^{2}}\]\\[\frac{{{l}_{1}}}{{{l}_{2}}}=1:1\]You need to login to perform this action.
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