A) \[\frac{1}{\eta }=\frac{1}{3\gamma }+\frac{1}{9K}\]
B) \[\frac{1}{K}=\frac{1}{3\gamma }+\frac{1}{9\eta }\]
C) \[\frac{1}{\gamma }=\frac{1}{3K}+\frac{1}{9\eta }\]
D) \[\frac{1}{\gamma }=\frac{1}{3\eta }+\frac{1}{9K}\]
Correct Answer: D
Solution :
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