Direction: What approximate value should come in place of question mark (?) in the question? |
A) 4
B) 5
C) 9
D) 10
E) 16
Correct Answer: E
Solution :
\[283\times \sqrt{?}=84.85\times 12.02+\sqrt{48.88}\times 16.06\] or, \[283\times \sqrt{?}\approx 85\times 12+\sqrt{49}\times 16\] = 1020 + 7 \[\times \]16 = 1020 + 112 = 1132 Or, \[\sqrt{?}\approx \frac{1132}{283}=4\] \[\therefore ?\approx 4\times 4=16\]You need to login to perform this action.
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