Direction: What approximate value should come in place of question mark (?) in the question? |
A) 34
B) 49
C) 32
D) 28
E) 38
Correct Answer: C
Solution :
\[{{(?)}^{2}}=(127.998\times 10.012\times \sqrt{6400})\] \[\div 100\] \[\approx \frac{(128\times 10)\times \sqrt{6400}}{100}=\frac{128\times 10\times 80}{100}\] \[=128\times 8=1024\] \[\therefore ?\approx \sqrt{1024}=32\]You need to login to perform this action.
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