question_answer

0.34 gram of a hydrocarbon when treated with methyl magnesium iodide gives 112 mL of \[C{{H}_{4}}\]at STP. Possible structure of the hydrocarbon is

A)  \[{{\left( C{{H}_{3}} \right)}_{2}}CH-C\equiv C-H\]        

B)  \[C{{H}_{3}}-{{\left( C{{H}_{2}} \right)}_{3}}-C\equiv CH\]

C)  \[{{\left( C{{H}_{3}} \right)}_{3}}C-C\equiv C-H\]

D)  Both [b] and [c].