• # question_answer A beaker contains a 105 ml mixture of alcohol and water. 3/7 of the mixture is alcohol, the remainder is water. An additional quantity of 105 mL of alcohol is poured into the mixture. What is the ratio of the volume of alcohol to water in the new mixture? A)  3 : 7                             B)  3 : 4                 C)  5 : 2                 D)         1 : 1

The amount of alcohol in the old mixture is $\frac{3}{7}\times 105=45\,\text{mL}$. Further, 105 mL alcohol is added Therefore, total alcohol in new mixture is 150 mL water content is (105 - 45) = 60 mL. Alcohol to water ratio is 150 : 60 or 5 : 2.