A) \[l+p\]
B) \[m-q\]
C) \[\frac{l-p}{m-q}\]
D) \[\frac{m-q}{l-p}\]
Correct Answer: D
Solution :
Since, \[(x+k)\] is a factor of each one of the given expression. Since, \[x=-k\] will make each zero. \[\therefore \] \[{{k}^{2}}-pk+q={{k}^{2}}-lk+m=0\] \[\therefore \] \[k=\frac{m-q}{l-p}\]You need to login to perform this action.
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