• # question_answer If $x+y=5$ and $xy=6,$ then the value of $\frac{1}{{{x}^{2}}}+\frac{1}{{{y}^{2}}}$ will be A)  $\frac{13}{24}$ B)  $\frac{11}{30}$ C)  $\frac{13}{32}$ D)  $\frac{13}{36}$

$\frac{1}{{{x}^{2}}}+\frac{1}{{{y}^{2}}}=\frac{{{x}^{2}}+{{y}^{2}}}{{{x}^{2}}{{y}^{2}}}=\frac{{{(x+y)}^{2}}-2xy}{{{(xy)}^{2}}}$ $=\frac{{{(5)}^{2}}-2(6)}{{{(6)}^{2}}}=\frac{25-12}{36}=\frac{13}{36}$