• question_answer A bag contains rupees, 50 paise, 25 paise and 10 paise coins in the proportion 1 : 3 : 5 : 7. If the total amount is ? 22.25. Find the number of coins of each kind. A)  5, Rs.1; 15, 50 paise; 25, 25 paise and 35, 10 paise B)  5, Rs.1; 25, 50 paise; 35, 25 paise and 15, 10 paise C)  5, Rs.1; 35, 50 paise; 15, 25 paise and 25, 10 paise D)  None of the above

Let the number of coins be x. 3x, 5x and 7x respectively as rupees, 50 paise, 25 paise and 10 paise. Since, Number of coins $x$ Value of coin in rupee = Amount in rupees Now, value of 50 paise coin in rupee $=\frac{1}{2}$ Value of 25 paise coin in rupee $=\frac{1}{4}$ Value of 10 paise coin in rupee $=\frac{1}{10}$ $\therefore$$\left[ (x\times 1)+\left( 3x\times \frac{1}{2} \right)+\left( 5x\times \frac{1}{4} \right)+\left( 7x\times \frac{1}{10} \right) \right]=22.25$ $\Rightarrow$ $\frac{89x}{20}=22.5$ $\therefore$ $x=5$ $\therefore$ Number of rupee coins $=5\times 1=5$ Number of 50 paise coins $=3x=3\times 5=15$ Number of 25 paise coins $=6x=5\times 5=25$ Number of 10 paise coins $=7x=7\times 5=35$
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