A) 50 m
B) 80 m
C) 72 m
D) None of these
Correct Answer: A
Solution :
Speed of faster train relative to slower one \[=(46-36)\,km/h=\left( 10\times \frac{5}{18} \right)m/s\] \[=\frac{25}{9}m/s\] Distance covered in \[36s=\left( \frac{25}{9}\times 36 \right)=100\,m\] \[\therefore \] 2 (length of each train) = 100 m \[\therefore \] length of each train = 50 mYou need to login to perform this action.
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