A) 0
B) 1
C) 13
D) 26
Correct Answer: A
Solution :
If \[a,\,b,\,c,\,...,\,x,\,y,\,z\] are 26 natural number then \[(x-a)\,(x-b)...\,\,(x-x)\,(x-y)\,\,(y-z)\] \[=\,(x-a)\,(x-b)\,...\,0\,(x-y)\,(x-z)\]\[=0\]You need to login to perform this action.
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