A) 6 m
B) 8 m
C) 5 m
D) 10 m
Correct Answer: C
Solution :
Area of ceiling = \[\frac{Total\,\cos t}{Cost\,of\,1\,sq\,unit}\] \[=\frac{270}{0.5}=540\,sq\,m\] Now, sine \[l\,:\,b=5x\,:\,3x\] \[\Rightarrow \] \[l\times b=15{{x}^{2}}=540\,{{m}^{2}}\] \[\Rightarrow \] \[l=30\,\,m\] and \[b=18\,m\] Now, area of the 4 walls \[\frac{Total\,\cos t}{Cost\,of\,1\,sq\,unit}\] \[=\frac{48}{0.1}=480\,{{m}^{2}}\] \[\therefore \] \[Height=\frac{480}{2\,(30+18)}=5\,m\]You need to login to perform this action.
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