A) 2 : 1
B) 2 : 3
C) 3:2
D) 1 : 2
Correct Answer: A
Solution :
Weight of copper in 17 kg 500 g i.e., 17500 g of alloy \[=\frac{5}{7}\times 17500=12500\,g\] and weight of zinc = (17500 -12500) = 5000 g Since, 1250 g of zinc is mixed in alloy. \[\therefore \] Total weight of zinc = 1250 + 5000 = 6250 g \[\therefore \] Required ratio = 12500: 6250 = 2 : 1You need to login to perform this action.
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