• # question_answer A thief running at 8 km/h is chased by a policeman whose speed is 10 km/h. If the thief is 100 m ahead of the policeman, then the time required for the policeman to catch thief will be A)  2 min             B)  6 min C)  10 min            D)  3 min

Correct Answer: D

Solution :

The distance overcome by the policeman in 1 h = 10 - 8 = 2 km 2000 m distance is overcome in 60 min. $\therefore$ 100 m distance is over come in $\frac{60\times 100}{2000}=3$ min

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