• # question_answer Find the surface area of a cuboid 10 m long, 5 m broad and 3 m high. A)  104 sq m         B)  140 sq m C)  170 sq m          D)  190 sq m

Given that, $l=10\,m,$ $b=5\,m,$ $h=3\,m$ $\therefore$ $lb=10\times 5=50\,{{m}^{2}}$ $bh=5\times 3=15\,{{m}^{2}}$ $hl=10\times 3=30\,{{m}^{2}}$ $\therefore$ Surface area $=2(lb+bh+hl)$ $=2(50+15+30)$ $=2\times 95$ $=190\,sq\,m$