A) 2 days
B) 3 days
C) 4 days
D) 5 days
Correct Answer: C
Solution :
Work done by 8 men in 6 days \[=\frac{6}{12}=\frac{1}{2}\] \[\therefore \] Remaining work \[=1-\frac{1}{2}=\frac{1}{2}\] Since 4 more men are engaged. \[\therefore \] Total number of men = 8 + 4 =12 By work and time formula. \[\frac{{{W}_{1}}}{{{M}_{1}}{{D}_{1}}}=\frac{{{W}_{2}}}{{{M}_{2}}{{D}_{2}}}\] \[\Rightarrow \] \[\frac{1}{8\times 12}=\frac{1/2}{12\times {{D}_{2}}}\] \[\therefore \] \[{{D}_{2}}=\frac{1}{2}\times \frac{8\times 12}{12}=4\] days
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