A) 10 m
B) 12 m
C) 14 m
D) None of the above
Correct Answer: A
Solution :
Let the length of rectangle \[=x\,m\] and its breadth = y m Also, let the side of the square be z m. Then, \[2(x+y)=4z=48\] \[\Rightarrow \] \[x+y=24\] and \[z=12\] Also, \[{{z}^{2}}-xy=4\] \[\Rightarrow \] \[xy={{z}^{2}}-4=144-4=140\] So, \[{{(x-y)}^{2}}={{(x+y)}^{2}}-4\,xy\] \[=576-560=16\] \[\therefore \] \[x-y=4\] and \[x+y=24\] On solving the above equations, we get \[2y=20\] \[\therefore \] \[y=10\,m\]You need to login to perform this action.
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