A) \[\frac{31}{16}\]
B) \[\frac{12}{19}\]
C) \[\frac{35}{17}\]
D) \[\frac{38}{17}\]
E) None of these
Correct Answer: A
Solution :
Let \[\frac{a}{7}=\frac{b}{8}=\frac{c}{16}=k\] Then a = 7k, b = 8k and c = 16 k \[\therefore \]\[\frac{a+b+c}{c}=\frac{(7+8+16)k}{16k}=\frac{31}{16}\]You need to login to perform this action.
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