A) 54
B) 154
C) 52
D) 100
E) 104
Correct Answer: E
Solution :
Let the three numbers be a, b and c respectively. Now, \[\left( \frac{a+b}{2} \right)-\left( \frac{b+c}{2} \right)=52\] or, \[a+b-b-c=52\times 2=104\] \[\therefore a-c=104\] a+b+k+360= 1700 Or, a+b+k=1340 ?.... (i) Again, a + c + k + 420 = 1740 or, a+c+k=1320 ... (ii) b+c+k+220= 1600 or, b+c +k= 1380 .. (iii) a + b + c + k + 360 + 220 + 420 = 2500 or, a+ b + c + k = 2500 - 1000 = 1500 ... (iv) Solving (i), (ii), (iii) and (iv), we get k=1040 or, a= 120, b= 180, c == 160You need to login to perform this action.
You will be redirected in
3 sec