A) 5.5 hours
B) 3.5 hours
C) 6 hours
D) 7 hours
E) 6.5 hours
Correct Answer: C
Solution :
If all pipes are opened together, in one hour they will fill \[\frac{1}{8}+\frac{1}{12}-\frac{1}{24}=\frac{3+2-1}{24}=\frac{1}{6}\] Part of the Tank. Hence the tank will completely fill in 6 hours. Method II. LCM of 8, 12 and 24 = 24 \[\therefore \]Total capacity of tank = 24 units \[\therefore \] Pipe Q fills in one hour \[\frac{24}{8}\] = 3 unit/hour R fills in one hour\[=\frac{24}{12}=2\] units/h S empties in one hour\[=\frac{24}{24}=1\] unit/h Time taken to fill the tank \[=\frac{24}{3+2-1}\] = 6 hoursYou need to login to perform this action.
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