| Quantity I. The probability of their being 2 pink and 2 .black |
| Quantity II. The probability of their being 2 pink, 1 black and 1 white |
A) Quantity I > Quantity II
B) Quantity I < Quantity II
C) Quantity I > Quantity II
D) Quantity I < Quantity II
E) No relation between Quantity I and Quantity II
Correct Answer: B
Solution :
Total number of balls = 6 + 5 + 4 = 15 Four balls are chosen at random Then, \[n(S){{=}^{15}}{{C}_{4}}=1365\] Quantity I.\[n(E){{=}^{6}}{{C}_{2}}{{\times }^{5}}{{C}_{2}}{{\times }^{4}}{{C}_{0}}=150\] \[P(E)=\frac{150}{1365}\] Quantity II.\[n(E){{=}^{6}}{{C}_{2}}{{\times }^{5}}{{C}_{1}}{{\times }^{4}}{{C}_{1}}=300\] \[P(E)=\frac{300}{1365}\] Hence, Quantity 1 < Quantity 11
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