| Direction: In the following questions two quantities I and II are given. Solve both the quantities and choose the correct option accordingly. |
| I. Selling price for Nitin so as to obtain a profit of 40%. Nitin sold his DSLR to Romit at a profit of 20%. Romit sold it to Abhi for Rs.18000 and earned a profit of Rs. 1500. |
| II. Nitin marked his DSLR 80% above the cost price and sold it at two consecutive discounts of 15% and 20% and earned a profit of Rs.2800. Find the selling price. |
A) Quantity I > Quantity II
B) Quantity II > Quantity I
C) Quantity I > Quantity II
D) Quantity I < Quantity II
E) Quantity I = Quantity II or relation can't be established.
Correct Answer: A
Solution :
Quantity I. Selling price for Remit = Rs. 18000 Profit = Rs. 1500 Cost price for Romit = 18000 - 1500 = Rs. 16500 \[\therefore \] Cost price for Nitin = \[16500\times \frac{100}{120}\] = Rs. 13750 \[\therefore \] Reqd veiling price or Nitin at 40% profit \[=13750\times \frac{140}{100}=Rs.\,19250\] Quantity II. Let cost price be Rs. 100. Market price = Rs. 180 Equivalent discount of 2 successive discounts of 20% and 15% = \[20+15-\frac{20\times 15}{100}=32%\] Profit is Rs. 22.4 on Rs. 100. \[\therefore \] Profit is Rs. 2800 on \[2800\times \frac{100}{22.4}\]= Rs. 12500 \[\therefore \]Selling price \[=\frac{12500\times 122.4}{100}\]= Rs. 15300 Hence Quantity I > Quantity II
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