| Direction: In the following questions two quantities I and II are given. Solve both the quantities and choose the correct option accordingly. |
| I. 12 men can do a piece of work in 15 days. They started working and after 10 days, they found that only 50% of the work had been done. How many more men are required to be hired to complete the work on time? |
| II. 4 men can do a piece of work in 6 days while 3 women can complete the same piece of work in 16 days. In how many days can 1 man and 2 women complete the work? |
A) Quantity I > Quantity II
B) Quantity II > Quantity I
C) Quantity I > Quantity II
D) Quantity I < Quantity II
E) Quantity I = Quantity II or relation can't be established.
Correct Answer: E
Solution :
Quantity I. Total work \[=12\times 15=180\]units Work done in 10 days = 90 units Work left = 90 units Now, \[\frac{12\times 10}{90}=\frac{(12+x)\,5}{90}\] or, 120 = 60 + 5x Quantity II. \[4M\times 6D=3W\times 16D\] \[\frac{M}{W}=\frac{2}{1}\] Total work \[=4M\times 6D=4\times 2\times 6=48\] or, 1M + 2W or. 2 + 2 = 4 Reqd no, of days \[=\frac{48}{4}=12\] Hence, Quantity I = Quantity II
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