A) Rs. 11520
B) Rs. 10102
C) Rs. 13216
D) Rs. 12600
E) None of these
Correct Answer: D
Solution :
\[\frac{P\times 12\times 4}{100}+(P+200)\left[ {{\left( 1'+\frac{10}{100} \right)}^{2}}-1 \right]=4320\] or, \[\frac{12P}{25}+(P+200)\left[ \frac{121}{100}-1 \right]=4320\] or, \[\frac{12P}{25}+(P+200)\times \frac{21}{100}=4320\] or, \[\frac{48P+(P+200)21}{100}=4320\] or, \[69P+4200=432000\] or, \[69P=427800\] or, \[P=Rs.\,6200\] \[\therefore \] \[P+200=Rs.\,6400\] \[\therefore \]Total investment = 6200 + 6400 = Rs. 12600You need to login to perform this action.
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