Direction: In each of the following questions read the given statements and compare the given two quantities on its basis. |
A) Quantity I > Quantity II
B) Quantity I \[\ge \] Quantity II
C) Quantity I \[\le \] Quantity II
D) Quantity I < Quantity II
E) No relation between Quantity I and II
Correct Answer: A
Solution :
\[{{({{x}^{b}})}^{e}}={{x}^{e}}\] \[\Rightarrow \]\[be=e\] \[\Rightarrow \]\[b=1\,\,(\because \,e\ne o)\] Now, \[\frac{{{x}^{3c}}}{{{x}^{b}}}=({{x}^{7b}})\times ({{x}^{y}})\times ({{x}^{2e}})\] Putting the value of b = 1 in equation (i), we get or, \[\frac{{{x}^{3c}}}{{{x}^{1}}}={{x}^{7}}\times {{x}^{y}}\times {{x}^{2c}}\] or, \[3c-1=7+y+2c\] or, \[3c-2c-y=7+1\] or, \[c-y=8\] or, \[c=8+y\] Hence \[c>y\]You need to login to perform this action.
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