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Banking Sample Paper IBPS PO (PT) Sample Test Paper-1

  • question_answer
    Direction: In the following questions two equations numbered I and II have been given. Solve both the equations and give answer.
    I. \[\frac{11}{\sqrt{x}}+\frac{4}{\sqrt{x}}=\sqrt{x}\] II. \[{{y}^{2}}-\frac{{{13}^{\frac{5}{2}}}}{\sqrt{y}}=0\]

    A)  \[x<y\]

    B)  \[x>y\]

    C)  \[x=y\] or no relation can be established

    D)  \[x<y\]

    E)  \[x>y\]

    Correct Answer: E

    Solution :

     I. \[\frac{11}{\sqrt{x}}+\frac{4}{x}=\sqrt{x}\] \[\therefore 11\div 4=15\] II. \[{{y}^{2}}-\frac{{{13}^{\frac{5}{2}}}}{\sqrt{y}}=0\] Or, \[{{y}^{\frac{5}{2}}}={{13}^{\frac{5}{2}}}\] \[\therefore y=13\] Hence \[x>y\]


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