Direction: In the following questions two equations numbered I and II have been given. Solve both the equations and give answer. |
A) \[x<y\]
B) \[x>y\]
C) \[x=y\] or no relation can be established
D) \[x<y\]
E) \[x>y\]
Correct Answer: E
Solution :
I. \[\frac{11}{\sqrt{x}}+\frac{4}{x}=\sqrt{x}\] \[\therefore 11\div 4=15\] II. \[{{y}^{2}}-\frac{{{13}^{\frac{5}{2}}}}{\sqrt{y}}=0\] Or, \[{{y}^{\frac{5}{2}}}={{13}^{\frac{5}{2}}}\] \[\therefore y=13\] Hence \[x>y\]You need to login to perform this action.
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