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Banking Sample Paper IBPS PO (PT) Sample Test Paper-2

  • question_answer
    Pipe P and Q can fill a tank in 10 hours and 6 hours respectively. After a certain time. Pipe P was closed. It took a total of 4 hours to fill the tank completely. For how many hours did Pipe P work?

    A)  \[2\frac{2}{3}\] Hours              

    B)  \[3\frac{2}{3}\]hours

    C)  \[3\frac{1}{3}\] Hours              

    D)  \[4\frac{1}{3}\]hours

    E)  \[2\frac{1}{3}\]hours

    Correct Answer: C

    Solution :

     Let Pipe P remain open for x hours Then-\[\frac{x}{10}+\frac{4}{6}=1\] \[or\,\,\frac{x}{10}=1-\frac{2}{3}=\frac{1}{3}\] \[\therefore x=\frac{10}{3}=3\frac{1}{3}hours\] Another Method: LCM of 10 and 6 = 30 units Now, Pipe P can fill\[\frac{30}{10}\]= 3 units/hour Pipe Q can fill \[\frac{30}{6}\]= 5 units/hour so, in four hours Pipe Q can fill \[5\times 4=20\]units So, Pipe P can fill the remaining (30 - 20 =) 10 units  in \[\frac{10}{3}=3\frac{1}{3}\]hours Hence Pipe P remains open for \[3\frac{1}{3}\]hours


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