A) 120 kg
B) 100kg
C) 160 kg
D) 180kg
E) 105kg
Correct Answer: D
Solution :
Suppose he sells x kg at 10% profit and the remaining pan (300 - x) kg at 15% loss. Now \[x\times \frac{110}{100}+(300-x)\times \frac{85}{100}=300\times \frac{95}{100}\] Or, \[\frac{11x}{10}-\frac{17x}{20}=285-255\] \[\frac{22x-17x}{20}=30\] Or, \[x=\frac{30\times 20}{5}=120kg\] The quantity he sells at 15% loss = (300 -120) = 180 kg By Allegation Method: Reqd quantity at 15% loss \[=\frac{300}{5}\times 3=180kg\]You need to login to perform this action.
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