A) \[\frac{105}{375}\]
B) \[\frac{15}{34}\]
C) \[\frac{5}{34}\]
D) \[\frac{113}{375}\]
E) \[\frac{19}{34}\]
Correct Answer: B
Solution :
Total no. of apples = 18 \[n(S){{=}^{18}}{{C}_{3}}=\frac{16\times 17\times 18}{1\times 2\times 3}=816\] \[n(E){{=}^{10}}{{C}_{2}}{{\times }^{8}}{{C}_{1}}=45\times 8=360\] \[\therefore P(E)=\frac{n(E)}{n(S)}=\frac{360}{816}=\frac{15}{34}\]
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