JEE Main & Advanced Sample Paper JEE Main - Mock Test - 10

  • question_answer
    Graph showing the electric potential V versus distance r from the centre of two concentric conducting spherical shells is as shown in the figure. The outer shell is thick and has total charge Q with inner radius 2a and outer radius 3a, the inner shell is thin having radius a and is earthed.

    A)    

    B)

    C)             

    D)

    Correct Answer: B

    Solution :

    [b] The potential of inner shell should be zero. \[V=\frac{Kq}{a}-\frac{Kq}{2a}+\frac{K(Q+q)}{3a}=0\] \[\frac{q}{2}+\left( \frac{Q+q}{3} \right)=0;\,\,\,q=\frac{-2Q}{5}\] \[V(a<r<2a)=\frac{2KQ}{5}\left[ \frac{1}{a}-\frac{1}{r} \right]\] Hence potential will increase up to \[r=2a\]. \[V(2a<r<3a)=\frac{KQ}{5a}\] For \[2a<r<3a,\] the potential will be constant. \[V(r>3a)=\frac{K\left[ \frac{3Q}{5} \right]}{r}\]


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