A) \[5\hat{i}-4\hat{j}\]
B) \[-5\hat{i}+4\hat{j}\]
C) \[10\hat{i}+4\hat{j}\]
D) \[10\hat{i}-4\hat{j}\]
Correct Answer: B
Solution :
[b] \[\alpha ={{a}_{0}}/r=10/2=5\,rad/{{s}^{2}}\] \[{{({{a}_{P,g}})}_{t}}=-10\hat{i}+5\hat{i}=-5\hat{i}\] \[{{({{a}_{P,g}})}_{n}}={{\omega }^{2}}r'=\frac{v_{0}^{2}}{{{r}^{2}}}\times r'=\frac{4\times 4}{2\times 2}\times 1=4\] \[\overrightarrow{a}=-5\hat{i}+4\hat{j}\]
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