A) 2
B) 2.57
C) 3
D) 3.75
Correct Answer: B
Solution :
[b]: Given data is 3, 10, 10, 4. 7, 10, 5 Here, n=7 Mean \[=\overline{x}=\frac{3+10+10+4+7+10+5}{7}=\frac{49}{7}=7\] Mean deviation from mean \[=\frac{\Sigma \left| {{x}_{i}}-\overline{x} \right|}{n}\] \[=\frac{4+3+3+3+3+2}{7}=\frac{18}{7}=2.57\]You need to login to perform this action.
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