A) 2
B) -1
C) 0
D) 1
Correct Answer: D
Solution :
[d]: \[\underset{x\to 0}{\mathop{\lim }} \left( \frac{1}{x}-\frac{2}{{{e}^{2x}}-1} \right)=\underset{x\to 0}{\mathop{\lim }}\,\frac{{{e}^{2x}}-1-2x}{x({{e}^{2x}}-1)}\] \[=\underset{x\to 0}{\mathop{\lim }}\,\frac{\left\{ \left( 1+2x+\frac{4{{x}^{2}}}{2!}+\frac{8{{x}^{2}}}{3!}+... \right)-1-2x \right\}}{x\left\{ \left( 1+2x+\frac{4{{x}^{2}}}{2!}+\frac{8{{x}^{2}}}{3!}+... \right)-1 \right\}}=1=f(0)\]You need to login to perform this action.
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