A) ethyl cyanide
B) ethyl amine
C) methyl amine
D) acetamide
Correct Answer: B
Solution :
\[\underset{Ethyl\,\,\text{amine}}{\mathop{{{C}_{2}}{{H}_{5}}N{{H}_{2}}}}\,\xrightarrow{HN{{O}_{2}}}\underset{Ethyl\,\,alcohol}{\mathop{{{C}_{2}}{{H}_{5}}OH}}\,\xrightarrow{PC{{l}_{5}}}{{C}_{2}}{{H}_{5}}Cl\]\[\xrightarrow{N{{H}_{3}}}\underset{Ethyl\,\text{amine}}{\mathop{{{C}_{2}}{{H}_{5}}N{{H}_{2}}}}\,\]
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