(i) The motion of particle is oscillatory |
(ii) The amplitude of particle is \[\frac{\alpha }{\beta }\] |
(iii) The mean position of particle is \[x=\frac{\alpha }{\beta }\] |
(iv) Maximum acceleration of particle is \[\frac{q}{\beta }\alpha \] |
A) Only (i) is correct
B) Only (i) and (iv) are correct
C) Only (i), (ii) and (iii) are correct
D) (i), (ii), (iii) and (iv) are correct
Correct Answer: D
Solution :
[d] Acceleration of particle \[{{a}_{P}}=\frac{qE}{m}=\frac{q\alpha }{m}-\frac{q\beta x}{m}\] Clearly the motion is oscillatory \[F=qE=0\] \[x=\frac{\alpha }{\beta }=\] Amplitude Maximum acceleration of particle w.r.t. observer is \[\frac{q\beta x}{m}=\frac{q.\beta }{m}\,\frac{\alpha }{\beta }=\frac{q.\alpha }{\beta }\]You need to login to perform this action.
You will be redirected in
3 sec