A) \[100\text{ }J\]
B) \[400\text{ }J\]
C) zero
D) \[160\text{ }J\]
Correct Answer: C
Solution :
[c] Maximum value of acceleration of 2 kg block is \[\frac{0.4\times 20}{2}=4\,m/{{s}^{2}}\] Common acceleration \[=\frac{5t-0.02t\times 50}{5}=t-0.2t=0.8t\] So both blocks move together upto \[0.8t=4\Rightarrow 5\sec \] Up to 5 sec, static friction works between 2 kg and kg blocks. \[\therefore \] The work done by friction on 2 kg block w.r.t. 3 kg is zero.You need to login to perform this action.
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