A) 8/729
B) 8/243
C) 1/729
D) 8/9
Correct Answer: B
Solution :
[b]: Possibility of getting a score 9 are (5, 4), (4, 5), (6, 3), (3, 6) Probability of getting score 9 in a single throw \[=p=\frac{4}{36}=\frac{1}{9}\] \[\therefore \]Required probability = probability of getting score 9 exactly twice \[{{=}^{3}}{{C}_{2}}{{\left( \frac{1}{9} \right)}^{2}}\times \left( \frac{8}{9} \right)=\frac{8}{243}.\]
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