A) \[\frac{T}{In\,\,2}\left| In\,\frac{2{{A}_{1}}}{{{A}_{2}}} \right|\]
B) \[T\,\left| In\,\frac{{{A}_{1}}}{{{A}_{2}}} \right|\]
C) \[\frac{T}{In\,2}\,\left| In\,\frac{{{A}_{2}}}{2{{A}_{1}}} \right|\]
D) \[T\,\left| In\,\frac{{{A}_{2}}}{2{{A}_{1}}} \right|\]
Correct Answer: C
Solution :
[c] \[{{A}_{1}}=\lambda {{N}_{0}}{{e}^{-\lambda {{t}_{1}}}}\,\,\,\Rightarrow \,\,\,{{t}_{1}}=\frac{1}{\lambda }In\left( \frac{\lambda {{N}_{0}}}{{{A}_{1}}} \right)\] \[{{A}_{2}}=\lambda \left( 2{{N}_{0}} \right){{e}^{-\lambda {{t}_{2}}}}\] So, \[{{t}_{1}}-{{t}_{2}}=\frac{T}{In\,\,2}\left| In\,\,\frac{{{A}_{2}}}{2{{A}_{1}}} \right|\]You need to login to perform this action.
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