A) Decreases by 1%
B) Increases by 8%
C) Decreases by 8%
D) Increases by 1%
Correct Answer: D
Solution :
[d] \[\omega =\sqrt{\frac{k}{m}-\frac{{{r}^{2}}}{4{{M}^{2}}}}=\sqrt{\frac{k}{m}}\,{{\left( 1-\frac{{{r}^{2}}}{4mk} \right)}^{\frac{1}{2}}}\] \[=\sqrt{\frac{k}{m}}{{\left( 1-\frac{0.08}{4} \right)}^{\frac{1}{2}}}=\sqrt{\frac{k}{m}}\left( 1-\frac{0.08}{2\times 4} \right)=\sqrt{\frac{k}{m}}(0.99)\] \[\omega \] decreases by\[1%\]. Hence T increases by \[1%\].You need to login to perform this action.
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