A) 3
B) 1
C) 4
D) 5
Correct Answer: C
Solution :
| Using \[\frac{1}{\lambda }=R{{(Z-1)}^{2}}\left[ \frac{1}{n_{2}^{2}}-\frac{1}{n_{1}^{2}} \right]\] |
| For a particle, \[{{n}_{1}}=2,\,{{n}_{2}}=1\] |
| Form metal A: \[\frac{1875R}{4}=R{{({{Z}_{1}}-1)}^{2}}\left( \frac{3}{4} \right)\Rightarrow {{Z}_{1}}=26\] |
| Form metal B: \[675\,R=R{{({{Z}_{2}}-1)}^{2}}\left( \frac{3}{4} \right)\Rightarrow {{Z}_{2}}=31\] |
| Therefore, 4 elements lie between A and B |
| \[=220\,MeV.\] |
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